Question

2. Se descompun termic 2000 kg de calcar, CaCO3, de puritate 80%.Calculati masa si numarul de moli de var nestins, CaO, format. (Aca-40, Ac-12, Ao-16) ​

Answer 1

Răspuns:

100kg CaCO3................80kg CaCO3 pur

2000kg CaCO3..............x kg CaCO3 pur

x=2000x80/100=1600kgCaCO3 pur

MCaCO3=40+12+3x16=100kg/kmol

MCaO=40+16=56kg/kmol

100kg......56kg

CaCO3 → CaO + CO2↑

1600kg......ykg

y=1600x56/100=896kg CaO

calculam in moli

nCaCO3=1600/100=16moli

1mol.........1mol

CaCO3 → CaO + CO2↑

16moli.......z moli

z=16x1/1=16moli CaO

Explicație: