Question

2 sin 3x + 1 =0 ; radical din 2 sin 5x + 1=0 si tg 3x + radical din 3=0

Answer 1

2sin3x+1=0
Sin3x=-1/2
Sin210°=-1/3 ==>x=70°

√2sin5x+1=0
Sin5x=-1/√2=-√2/2
Sin225°=-√2/2 ===>x=45°

Tg3x+√3=0
Tg3x=-√3
Tg120°=-√3 ==>x=40°

Answer 2

$2sin3x=-1 \\ sin3x=- \frac{1}{2} \\ 3x=(-1)^n*(- \frac{ \pi }{6})+n \pi \\ x=( -1)^{n+1}* \frac{ \pi }{18}+ \frac{n \pi }{3},n...apartine...Z$$\sqrt{2sin5x}+1=0 \\ 2sin5x=-1 \\ 5x=( -1)^{k+1}* \frac{ \pi }{6}+k \pi \\ x=( -1)^{k+1}* \frac{ \pi }{30}+ \frac{k \pi }{5}.k...apartine...Z$
$tg3x+ \sqrt{3}=0 \\ tg3x=- \sqrt{3} \\ 3x=- \frac{ \pi }{6}+l \pi \\ x=- \frac{ \pi }{18}+ \frac{l \pi }{3},l....apartne,,,,Z$