Question

2 sin60 - 4 cos30 + 3 tg60 =?
vreau rezolvarea

Answer 1

$2sin60-4cos30+3tg60= \\ =2* \frac{ \sqrt{3} }{2}-4* \frac{ \sqrt{3} }{2}+3 \sqrt{3} = \\ = \sqrt{3}-2 \sqrt{3}+3 \sqrt{x} 3= \\ =2 \sqrt{3.}$

Answer 2

sin 60 = radical 3/ 2
cos 30 = radical 3 /2
tg 60 = radical 3
2*rad3/2 - 4*rad3/2 + 3*rad3 = -2rad3/2 + 43rad 3 = (-2 +6)rad 3 = 4 rad 3