Question

2
$( \sqrt{2 } - 3) {}^{2} + \sqrt{72 } = 11$
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Answer 1

(√2-3)²+√72=11

(a-b)²=a²-2ab+b²

⇒√2²-2√2 ·3+3²+√72=11

2-2√2 ·3 +3²+√72=11

2-6√2+9+6√2=11  -se simplifica

2+9=11

11=11 ⇒ Adevarat

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