Question

(2*totul supra x+1* +x*totul supra 1-x*la puterea 2** -3x+6*totul supra x*la puterea 2*+x-2*):1*totul supra1-x*=2x+5*totul supra x+1*

Answer 1

[2/(x+1) + x/(1-x)²- (3x +6)/(x² + x-2)] : 1/(1-x) = (2x+5)/(x+1)
[2/(1+x) + x/(1-x)² - 2(x+2)/(x+2)(x-1)] : 1/(1-x) = (2x+5)/(x+1)
[2/(1+x) + x/(1-x)² + 2/(1-x)] ÷ 1/(1-x) = (2x+5)/(x+1)
[2(1-x)² + x + 2(1-x)]/(1-x)² · (1-x) = (2x+5)/(x+1)
(2 - 4x +2x² + x +2 - 2x)/(1-x) = (2x+5)/(x+1)
(4 -5x + 2x²)/1-x) = (2x+5)/(x+1)
(4-5x +2x²)(x+1) = (2x+5)(1-x)
4x - 5x² + 2x³ + 4 - 5x + 2x² = 2x + 5 - 2x² - 5x
2x³ - 3x² - x + 4 = - 2x² -3x +5    2x³ - x² +2x - 1 = 0    x²(2x - 1) + (2x - 1) = 0
(x² + 1)(2x-1) = 0      2x - 1 = 0    x = 1/2    x² + 1 = 0  x²= -1    x ∉ R