Question

2^x-1+2^x+2^x+1+2^x+2+2^x+3=992
x=?

Answer 1

Salut,

Din enunț avem că:

$\dfrac{2^x}2+2^x+2\cdot 2^x + 4\cdot 2^x + 8\cdot 2^x = \left(\dfrac{1}2+15\right)\cdot 2^x=\dfrac{31\cdot 2^x}2=992,\\\\sau\;2^x=64=2^6,\ deci\ x=6.$

Green eyes.