Question

2^x+2^x+1=6 CUM SE REZOLVA ACEST EXERCITIU?

Answer 1

2^x + 2^(x+1) = 6
2^x + 2(2^x) =6
3(2^x) =6
2^x =2
2^x =2^1  => x=1

Answer 2

$2^\big x+2^{\big x+1}=6 \\ \\ 2^\big x+2^\big x\cdot 2 = 6 \\ \\ 2^\big x\cdot (1+2) = 6 \\ \\ 2^\big x \cdot 3 = 6 \\ \\ 2^\big x = \dfrac{6}{3} \\ \\ 2^\big x = 2 \\ \\ \big x = \log_\big2 2 \\ \\ \boxed{x = 1}$