Question

2 [(x+3) la a doua - 5 la a doua]÷11+2003 la zero= 3.
Aflati valoarea lui x.​

Answer 1

2[(x+3)²-5²]÷11+2003la 0=3

2[(x+3)²-25]÷11+1=3

2[(x+3)²-25]÷11=3-1

2[(x+3)²-25]÷11=2

2[(x+3)²-25]=2•11

2[(x+3)²-25]=22

(x+3)²-25=22÷2

(x+3)²-25=11

(x+3)²=11+25

(x+3)²=36

x²+3²=36

x²+9=36

x²=36÷9

x²=4

x=√4

x=2