Question

2^x 5-2^x 4-2^x 3-2^x 2-2^x 1-2^x=64

Answer 1

nici acum redactarea ta nu e corecta

Answer 2

Tot nu cred ca e scrisa corect !

Posibil sa fie asa:

2^(x+5)-2^(x+4)-2^(x+3)-2^(x+2)-2^(x+1)-2^x=64

Sau:

$2^{x+5}-2^{x+4}-2^{x+3}-2^{x+2}-2^{x+1}-2^x=64$


$2^x\cdot2^5-2^x\cdot2^4-2^x\cdot2^3-2^x\cdot2^2-2^x\cdot2-2^x=64$

Acum dam factor comun $2^x$, si obtinem:

[tex]2^x(2^5-2^4-2^3-2^2-2-1) = 64 \Longrightarrow 2^x(32-16-8-4-2-1) = 64 \Rightarrow 2^x\cdot1=64 \Rightarrow 2^x=2^6 \Rightarrow x=6[/tex]