Question

(2-x)(x+2)+$(x+3)^{2}$=5

Answer 1

$\displaystyle (2-x)(x+2)+(x+3)^2=5 \\ 2x+4-x^2-2x+x^2+2 \cdot x \cdot 3+3^2=5 \\ 2x+4-x^2-2x+x^2+6x+9=5 \\ 2x-x^2-2x+x^2+6x=5-4-9 \\ 6x=-8 \\ x=- \frac{8}{6} \\ x=- \frac{4}{3}$