Question

(2-x)(x+2)+$(x+3)^{2}$=?
x= $- \frac{4}{3}$

Answer 1

$\displaystyle (2-x)(x+2)+(x+3)^2 \\ x=- \frac{4}{3} \\ \left[2-\left( -\frac{4}{3} \right)\right] \left(- \frac{4}{3} +2 \right)+\left(- \frac{4}{3} +3\right)^2= \\ \\ =\left(2+ \frac{4}{3} \right)\left(- \frac{4}{3} +2 \right)+\left(- \frac{4}{3} \right)^2+2 \cdot \left(- \frac{4}{3} \right) \cdot 3+3^2= \\ \\ =- \frac{8}{3} +4- \frac{16}{9} + \frac{8}{3} + \frac{16}{9} - \frac{24}{3} +9= \\ \\ =4- \frac{24}{3} +9=4-8+9=-4+9=5$