Question

2(y+3)-4(x+1)=8
2(x+y+1)-3(y+2x+1)=0​

Answer 1

Răspuns:

$\left \{ {{2(y+3)-4(x+1)=8} \atop {2(x+y+1)-3(y+2x+1)=0}} \right.$

$\left \{ {{2y+6-4x-4=8} \atop {2x+2y+2-3y-6x-3)=0}} \right.$

$\left \{ {{2y-4x=6} /:2 \atop {-4x-y=1}} \right.$

$\left \{ {{y-2x=3} \atop {-y-4x=1}} \right.$   +

 /    -6x=4 /:(-2)  3x=-2  ⇒ x=$-\frac{2}{3}$

y -2($-\frac{2}{3}$)=3       y+ $\frac{4}{3}$ =3 /*3    3y+4=9    3y=5 ⇒ y= $\frac{5}{3}$

Explicație pas cu pas: