Question

20. Calculati:
a) 3,52 +[(14,2–5).0,08] 0,625 – 4,2; d) 1,2.[(0,2-1,5+0,2-10).100]+2,1²;
b) 2,5-[(4,12+3,88)-3,6]-4,5-0,12; e) (12,8.25 – 1,8-(1,7-0,6+3,4-5)]: 100.
c) (12,5+0,5-(145,2+3,15-100)] 10–10,5;
(nota 9)​

Answer 1

20.

a) 3,52 +[(14,2–5) 0,08] 0,625 – 4,2= 3,52+ (9,2 ×0,08) 0,625= 3,52+ 0,736 × 0,625= 3,52 + 0,46= 3,98

b) 2,5-[(4,12+3,88)-3,6]-4,5-0,12= 2,5-(8-3,6)-4,5-0,12= 2,5-4,4-4,5-0,12= -6.52

c) [12,5+0,5-(145,2+3,15-100)] 10–10,5= (12,5+0,5-48,35) 10 -10,5= -35,35×10-10,5= -352,5-10,5= -365