Question

20. Calculaţi:
a)radical din1/16:(radical4/9+radical49/36-radical9/144)

Answer 1

Răspuns:

$\sqrt\frac{1}{16}$$:(\sqrt \frac{4}{9} +\sqrt \frac{49}{36} -\sqrt \frac{9}{144}$$)=\frac{1}{4} :(\frac{2}{3} +\frac{7}{6} -\sqrt \frac{1}{16} )$[tex]=\frac{1}{4}:(\frac{2}{3}+\frac{7}{6}-\frac{1}{4})=\\ [/tex]$\frac{1}{4}:\frac{19}{12} =\frac{1}{4}*\frac{12}{19}=\frac{3}{19}$