Question

-20 radical din 18 : 4radical din 6=??

Answer 1

$\frac{-20 \sqrt{18} }{4 \sqrt{6} } = \frac{5*3 \sqrt{2} }{ \sqrt{6} } = \frac{15 \sqrt{2} \sqrt{6} }{6}= \frac{5 \sqrt{12} }{2} = \frac{5*2 \sqrt{3} }{2} =5 \sqrt{3}$