Question

(20.) Rezolvati in multimea numerelor rationale ecuatiile:
a)(x-2)^2 + 3x = x(x + 1);
b) (x + 3)(x-1)=(x+3)^2+8;
c)(x-1)^2-x(x+5)=3x +7
d) (x+3)(x-3)+2x = (x+4)^2 + 5;
e) (x+1)^2 -3(x+ 7) = 3+(x - 2)^2; f)(x+2)(x-2) + 4(x + 3) =(x+2)^2;
VA ROG FRUMOS
DAU COROANA!!!

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Answer 1

Răspuns:

Explicație pas cu pas:

a) x²-4x+4+3x=x²+x              2x=4     x=2

b)x²+3x-x-1=x²+6x+9+8    4x=-18    x=-9/2

c) x²-2x+1-x²-5x=3x+7    10x=-6   x=-3/5

d)x²-9+2x=x²+8x+16+5     6x=-30    x=-5

e)x²+2x+1-3x-21=3+x²-4x+4    3x=27   x=9

f)x²-4+4x+12=x²+4x+4       nu are solutie