Question

200÷{[(7×a+144)÷25+132]×5-600}=2+0÷10 alt ex. 7-[5200÷13-5×(360-2a)]÷20=2

Answer 1

200:{[(7×a+144):25+132]×5-600}=2+0:10
200:{[(7×a+144):25+132]×5-600}=2
[(7×a+144):25+132]×5-600=100
[(7×a+144):25+132]×5=100 +600
(7×a+144):25+132=700:5
(7×a+144):25=140-132
(7×a+144):25=8
7×a+144=8×25
7×a=200-144
7×a=56
a=8

 7-[5200:13-5×(360-2a)]:20=2
-[400-5×(360-2a)]:20=2-7
-[400-5×(360-2a)]:20=-5
400-5×(360-2a)=100
-5×(360-2a)=100-400
-5×(360-2a)=-300
5×(360-2a)=300
360-2a=60
2a=360-60
2a=300
a=150