Question

200-{90×[(9÷9×9)÷9]+10×10}=100-x

Answer 1

200-{90×[(9÷9×9)÷9]+10×10}=100-x
200-{90×[(1×9)÷9]+10×10}=100-x
200-[90×(9÷9)+10×10]=100-x
200-(90×1+10×10)=100-x
200-(90+100)=100-x
200-190=100-x
10=100-x
x=100-10
x=90

Answer 2

Răspuns

90 ;

Explicație pas cu pas:

200-{90x[(9:9x9):9]+10x10} = 100-x ;

200-{90x[(1x9):9]+100} = 100-x ;

200-[90x(9:9)+100] = 100-x ;

200-(90x1+100) = 100-x ;

200-190 = 100-x ;

x = 100-10 = 90 ;