Question

200g CaCo3 cu 5% impuritati reactioneaza cu HCl.Cata sol HCl de c=10% s-a consumat?

Answer 1

-calculez masa de carbonat de calciu pur  ,stiind p=95%
p=m,px100/m,impur
95/100= m,pur/200-----> m,pur=190g CaCO3 pur
-din ecuatia reactiei calculez masa de HCl
1mol              2mol
CaCO3   +    2HCl--------> CaCl2 +CO2+  H2O
100g.............2x36,5g
190g.............m=138,7gHCl=md
-calculez masa de solutie,ms, care contine md calculat
c= mdx100/ms
10/100= 138,7/ms------>ms=1387g

M(miu)HCl= 36,5g/mol      M,CaCO3=100g/mol