Question

{2017-[(2×a : 5 + 4 ) : 3 - 2 ]× 2017}× 2 - 2017 = 2017​

Answer 1

{{2017-[(2a+20)/5]/3-2}2017}2-2017=2017
{2017-[(2a+20)/15-2]2017}2-2017=2017
{2017-[(2a+20-30)/15]2017}2-2017=2017
{{2017-[(2a-10)2017]/15}2017}2-2017=2017
{2017-[(4034a-20170)/15]2017}2-2017=2017
2017[1-(4034a-20170)/15]2-2017=2017
2017{[1-(4034a-20170)/15]2-1}=2017
[1-(4034a-20170)/15]2-1=1
[1-(4034a-20170)/15]2=2
1-(4034a-20170)/15=1
(4034a-20170)/15=0
4034a-20170=0
4034a=20170 => a=5

Answer 2

Răspuns: $\red{\boxed{\bf a = 5}}$

Explicație pas cu pas:

Bună !

$\bf \Big\{2017-\big[\big(2\cdot a : 5 + 4 \big) : 3 - 2 \big]\cdot 2017\Big\}\cdot 2 - 2017 = 2017$

$\bf \Big\{2017-\big[\big(2\cdot a : 5 + 4 \big) : 3 - 2 \big]\cdot 2017\Big\}\cdot 2 = 2017+2017$

$\bf \Big\{2017-\big[\big(2\cdot a : 5 + 4 \big) : 3 - 2 \big]\cdot 2017\Big\}\cdot 2 = 4034~~~\bigg|:2$

$\bf 2017-\big[\big(2\cdot a : 5 + 4 \big) : 3 - 2 \big]\cdot 2017 = 2017$

$\bf 2017 = 2017 +\big[\big(2\cdot a : 5 + 4 \big) : 3 - 2 \big]\cdot 2017$

$\bf 2017 - 2017 =\big[\big(2\cdot a : 5 + 4 \big) : 3 - 2 \big]\cdot 2017$

$\bf 0 =\big[\big(2\cdot a : 5 + 4 \big) : 3 - 2 \big]\cdot 2017~~~\bigg|:2017$

$\bf 0 =\big(2\cdot a : 5 + 4 \big) : 3 - 2$

$\bf 0+2 =\big(2\cdot a : 5 + 4 \big) : 3$

$\bf 2 =\big(2\cdot a : 5 + 4 \big) : 3 ~~~\bigg|\cdot3$

$\bf 6 =2\cdot a : 5 + 4$

$\bf 6 -4=2\cdot a : 5$

$\bf 2=2\cdot a : 5~~~\bigg|\cdot 5$

$\bf 10=2\cdot a~~~\bigg|:2$

$\bf 5 = a$

$\red{\boxed{\bf a = 5}}$

P.S.: Dacă ești pe telefon te rog să glisezi spre stânga pentru a vedea întreaga rezolvare.

Baftă multă !