Question

2034-2×{7+[29-3×(a+2×b)]÷4}=2016

VĂ ROG SĂ MĂ AJUTATI

Answer 1

2034-2×{7+[29-3×(a+2×b)]÷4}=2016

2×{7+[29-3×(a+2×b)]÷4}=2034-2016

2×{7+[29-3×(a+2×b)]÷4} = 18

7+[29-3×(a+2×b)]÷4 = 18:2 = 9

[29-3×(a+2×b)]÷4 = 9-7 = 2

29-3×(a+2b) = 2×4 = 8

3×(a+2b) = 29 - 8 = 21

a + 2b = 21 : 3

a + 2b = 7

2b = par
7 = impar ==>
==> a = numar impar
==> a = 1; 3; 5
==> 2b = 7-1 = 6 ==> b = 3
==> 2b = 7-3 = 4 ==> b = 2
==> 2b = 7-5 = 2 ==> b = 1

deci, solutiile sunt:
(a ; b) = (1; 3); (3; 2) ; (5; 1)