Question

2¹×2²×2³......×2¹⁰×2¹¹ cine poate???​

Answer 1

Salut,

$2^1\cdot 2^2\cdot 2^3\cdot\ldots\cdot 2^{10}\cdot 2^{11}=2^{1+2+\ldots+10+11}=2^{\frac{10\cdot 11}2}=2^{55}.$

Am folosit formula lui Gauss pentru n = 11, adică:

$1+2+3+\ldots+n=\dfrac{n(n+1)}2.$

Green eyes.