Question

21,8 grame propan si butan formeaza prin ardere 33,6 litri dioxid de carbon.
Care este compozitia procentuala masica a amestecului initial? URGENT!!!

Answer 1

44*x + 58*y = 21.8;  22.4*(3*x + 4*y) = 33.6; x = 0.1; y = 0.3; 0.1 moli propan = 4.4g = 20.18%; 0.3 moli butan = 17.4 g = 79.82%.