Question

[2¹²*2¹⁸+25³⁵:5¹⁰-(3⁷)⁵]<:[4²*2⁵*2²¹+(5¹⁵)-(3⁵)⁷]=?​

Answer 1

Răspuns:

5 ^45

Explicație pas cu pas:

[2 ^12×2^18 +25^35:5^10-(3^7)^5]:[4^2×2^5×2^21+5^15-(3^5)^7]=

[2 ^(12+18)+(5^2) ^35:5^10-3^(7×5)]:[(2^2)^2×^(5+21)+5^15-3^(5×7)]=

[2^30+5^(2×35):5^10-3^35] :[2^(2×2)×2^26+5^15-3^35]=

(2^30+5^70:5^10-3^35):(2^4×2^26+5^15-3^35)=

(2^30+5^(70-10)-3^35):(2^(4+26)+5^15-3^35)=

(2^30+5^60-3^35):(2^30+5^15-3^35)=

2^30:2^30+5^60:5^15-3^35:3^35=

1 +5^(60-15)-1=

5 ^45