Question

22-[59+2×(5+7×i)-1]÷9=2( rez tre sa dea 8)
8+3×[4+5×(6+7×k)]-90=860 (rez tre sa dea 8)
8+1×[8+8×(8+8×j)]+308=900 (rez tre sa dea 8)
(1478-1125+y×2):7×4=500 (rez tre sa dea 261)

Answer 1

[tex]22-[59+2*(5+7i)-1]:9=2 \\ (68+14i):9=20|*9 \\ 68+14i=180|-68 \\ 14i=112|:14 \\ \underline{i=8} \\ \\ 8+3*[4+5*(6+7k)]-90=860|+90 \\ 8+3(4+30+35k)=950|-8 \\ 102+105k=942|-102 \\ 105k=840|:105 \\ \underline{k=8} \\ \\ 8+1*[8+8*(8+8j)]+308=900 \\ 388+64j=900|-388 \\ 64j=512|:64 \\ \underline{j=8} \\ \\ (1478-1125+2y):7*4=500|:4 \\ (353+2y):7=125|*7 \\ 353+2y=875|-353 \\ 2y=522|:2 \\ \underline{y=261} [/tex]