Question

[(2³+2⁴+2⁵+2⁶)÷(2²+2³)]×(1+3+3²+3³)=?
varog rqpid dau coroana la primul raspuns corect!​

Answer 1

Răspuns:

Explicație pas cu pas:

[(2³+2⁴+2⁵+2⁶)÷(2²+2³)]×(1+3+3²+3³)=?

[(2³+2⁴+2⁵+2⁶)÷(2²+2³)]×(1+3+3²+3³)=[2³·(1+2+2²+2³):2²(1+2)]·(1+3+9+27)=

[2³·(1+2+4+8):(2²·3)]·40=[(2³·15):(2²·3)]·40=2·5·40=10·40=400