Question

23+4×{5+2×[3×(x-2)+12]÷7-2}÷3=35​

Answer 1

$23 + 4(5 + 2(3(x - 2) + 12) \div 7 - 2) \div 3 = 35$

$23 + 4(5 + 2(3x - 6 + 12) \div 7 - 2) \times \frac{1}{3} = 35$

$23 + 4(5 + 2(3x - 6) \div 7 - 2) \div \frac{1}{3} = 35$

$23 + 4(5 + \frac{2(3x + 6)}{7} - 2) \times \frac{1}{3} = 35$

$23 + 4(5 + \frac{6x + 12}{7} - 2) \times \frac{1}{3} = 35$

$23 + 4(3 + \frac{6x + 12}{7} ) \times \frac{1}{3} = 35$

$23 + 4 \times \frac{21 + 6x + 12}{7} \times \frac{1}{3} = 35$

$23 + 4 \times \frac{33 + 6x}{7} \times \frac{1}{3} = 35$

$23 + 4 \times \frac{3(11 + 2x)}{7} \times \frac{1}{3} = 35$

$23 + 4 \times \frac{11 + 2x}{7} = 35$

$23 + \frac{4(11 + 2x)}{7} = 35$

$23 + \frac{44 + 8x}{7} = 35$

$161 + 44 + 8x = 245$

$205 + 8x = 245$

$8x = 245 - 205$

$8x = 40$

$x = 5$