Question

23 T 1. Calculează: a) (1+3.32.34): (37+1) = c) (4 + 2192 : 2188):5= e) 22 +24:2-07-15 = g) (30.3.35:35 +33): 15 = b) (62 +22 – 20): 13:37:36 +32 = d) 519.521: (3-11-168:6)38 = f) 2. [2+3. (23:2+3.32 -52)1=
ma puteti ajuta vă rog frumos
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Answer 1

Răspuns:

a) (1+3×32×34)÷(37+1)=

1+2×32×34=

1+2 176= 2 177

37+1=38

=> 2 177÷38=57.289...

c) (4+2 192÷2 188)÷5=

4+2 192÷2 188

4+1.001=5.001..

=> 5.001÷5=1.0002

e) 22+24÷2-7-15

22+12-7-15

34-7-15=12

g) (30×3×35÷35+33)÷15

30×3×35÷35

30×3×1

90×1=90

=> 90÷15=6

b) (62+22-20)÷13÷37÷36+32

62+22-20

84-20=64

64÷13÷37÷36+32

4.923÷37=0.133...

0.133÷36=0.003...

0.003+32=32.003

d) 519×521÷(3-11-168÷6)×38

3-11-168÷6

3-11-28=-36

519×521÷(-36)×38

519×14.47(2)×38

7511.80(3)×38=285,421.1(6)

f) 2×[2+3×(23÷2+3×32-52)×1]

23÷2+3×32-52

11.5+96-52

11.5+44=55.5

2+3×55.5×1=

2+166.5×1=

168.5×1=168.5

=> 2×168.5=337