Question

235-{16×100:[36-42:x
:(15:3-4:1)-20]+14×5}=5

Answer 1

235-{16×100÷[36-42÷x÷(15÷3-4÷1)-20]+14×5}=5

235-{16×100÷[36-42÷x÷(5-4)-20]+70}=5

236-{16×100÷[36-42÷x÷1-20]+70}=5

235-{16×100÷[36-42\pex-20]+70}=5

235-{16×100÷[16-42\pex]+70}=5

235-{16×100÷\16x-42\pex+70}=5

235-{16×100×x\pe16x-42+70}=5

235-{16×100×x\pe2(8x-21)+70}=5

235-{8×100×x\pe8x-21+70}=5

235-{800x\pe8x-21\+70}=5

235-800x\pe8x-21\-70=5

165-800x\8x-21\=5

-800x\pe8x-21\=5-165

-800x\pe8x-21=-160

-800x=-160(8x-21)

-800x=-1280x+3360

-800x+1280x=3360

480x=3360

x=7;
x≠21\pe8; x≠0..
x=7