Question

(2⁴+2⁶)²:(3²•11+1)+1²⁰⁰⁹
Va rog urgent am nevoie de ajutor!​

Answer 1

Răspuns:

2(4)= 2x2x2x2=4x4=16

2(6)= 16x2x2= 64

3(2)= 3x3=9

1(2009)= 1 (1 la orice putere pozitiva  rezultatul va fi 1)

(16+64)^2:(9x11+1)+1=

80^2:100+1=

6400:100+1=

64+1=65

cplll!!!

coroana pls? m-ar ajuta foarte mult!

Answer 2

$(2^4+2^6)^2:(3^2\cdot 11+1)+1^{2009}= \\ =(2^4(1+2^2)^2:(9\cdot 11+1)+1= \\ =(2^4)^2\cdot 5^2:(99+1)+1= \\ =2^8\cdot 25:100+1=\\=2^8:4+1= \\ =2^8:2^2+1=\\=2^6+1=\\=64+1=\boxed{65}$