Question

24. Determinați mulţimile:
a) A=xe Z\{2}
b)B= xe Z
c)C= {xeZ
√28-10√3+√5-2√6 +√√18+8√√2
E
[ez});
Fez):
x-2
√10-2√21+√39+12√3+√16-6√7
2x+1
√15-6√6 + √11-2√30 +√41+12√5 €Z
2x-1
EZ



DAU COROANA

Answer 1

Răspuns:

Explicație pas cu pas:

28 -10√3 = 25 -10√3 +3 = (5 -√3)^2

5 -2√6 = 3 -2√6 +2 = (√3 -√2)^2

18 +8√2 = 16 +8√2 +2 = (4 +√2)^2

5 -√3 +√3 -√2 +4 +√2 = 9

9/(x-2) in Z

x -2 in {-9; -1; 1; 9}

x-2 = -9,  x = -7

x -2 = -1,  x = 1

x -2 = 1,  x = 3

x - 2 = 9,   x = 11

A = {-7; 1; 3; 11}

10 -2√21 = 7 -2√21 +3 = (√7 -√3)^2

39 +12√3 = 36 +12√3 +3 = (6 +√3)^2

16 -6√7 = 9 -6√7 +7 = (3 -√7)^2

√7 -√3 +6 +√3 +3 -√7 = 9

9/(2x+1) in Z

2x +1 in {-9; -1; 1; 9}

2x +1 = -9,  x = -5

etc.