Question

[2⁵×(2×3)⁷]÷3⁷=2
cum aflu puterea
va rog a cum
sunt clasa a-v-a​

Answer 1

Explicație pas cu pas:

$\boxed {(a \cdot b)^{m} = a^{m} \cdot b^{m}} \: \: \boxed {a^{m} \cdot a^{n} = a^{m + n}} \: \: \boxed {a^{m} : a^{n} = a^{m - n}}$

$[ {2}^{5} \cdot {(2 \cdot 3)}^{7} ] : {3}^{7} = ({2}^{5} \cdot {2}^{7} \cdot {3}^{7} ) : {3}^{7} = \\ = ({2}^{5 + 7} \cdot {3}^{7} ) : {3}^{7} = {2}^{12} \cdot {3}^{7} : {3}^{7} = {2}^{12}$