Question

25-{27:[(a-27:3):3]+42:7×3}=4

{[(3×a-5)×3-5]×3-5}×3-5=261


Stie cineva regulile calculului invers ?????

Answer 1

1) {...} = 25-4 = {21} 21={27:[(a-9):3]+18} 21-18=3 27:3=[9] [9]=[(a-9):3] a=3*[9]+9 a=36 2) {....}=(261+5):3={88,666666..} [....]=(88,666666..+5):3=[31,222222..] (...)=(31,222222..+5):3=12,074074... a=(12,074074..+5):3=5,691358.. a=5,69135802466.