Question

{25-3•[2+(3+x):3]}•{[6•(y-2)-9]:3-4}=7

Answer 1

Explicație pas cu pas:

$\{25 - 3 \times [2 + (3 + x) \div 3]\} \times \{[6 \times (y - 2) - 9] \div 3 - 4 \} = 7$

$\{25 - [3 \times 2 + 3 \times (3 + x) \div 3]\} \times \{[6 \times (y - 2) \div 3 - 9 \div 3] - 4 \} = 7$

$\{25 - [6 + (3 + x)]\} \times \{[2 \times (y - 2) - 3] - 4 \} = 7$

$[25 - (6 + 3 + x)] \times [(2y - 4 - 3) - 4] = 7$

$(25 - 9 - x) \times (2y - 7 - 4) = 7$

$(16 - x) \times (2y - 11) = 7$

x ≠ 16

2y ≠ 11 => y ≠ 11/2

$16 - x = \frac{7}{2y - 11}$

$x = 16 - \frac{7}{2y - 11}$