Question

25) Calculaţi, respectând ordinea operatiilor
a)[(50 : 10 + 25) + 25] : 5 =
b)80+ [26-(81:9+4)] =
C) 200 – [50:5+ (76 - 28) + 7] + 15 =
d) 793 + 200 : 10 - [76 + (293 - 209)] =
e) [(4:4+4): 5+9] x 222 =
f) [(58 x 3 – 74) x 100 : 1000 + (111 x 9 +111)+889 =
g) 606 + 2484:9- [248 : 4+ ( 2596 - 2499) - 99] - 666 =
h) (6518 - 3462 - 362) - [2694 : (1103 - 1097)] =
i) 2976 + [(3785 – 2986) x 3] - 5188 =
j) [(2 + 2 + 2): 2 - 2 x 1] x [(3+3+3): 3 - 3 x 1] + 1 =
k) (280 – 78): 2 x 5 + [(378 + 88): 2 + 262] =
1) 2 x [(12 x 10:6-(200 - 20): 9+ 36:18 - 2) =
m) 1500 - 13 x 5+ [25 x (160 - 30 x 5) -8- (24 + 6:6)] =
n) 5x{32:8 +5x[40+8x(200:5 – 72: 2)} =
o) 0+6x{36:9+0x[37+9x(400:5–96:3)] =
p) 1500 + {250:5+ 5x [265 – (50:25+ 2)x 65}x150) =
q) 1278 – 2 x{316+ 4x[6+ (3 + 3x3):6] =
r) 16+ (15:3+3): 8+ [16-(3 x 20 - 50)- 5 + 6 + 3 =

Va rog

Answer 1

Explicație pas cu pas:

a)

[(50:10+25)+25]:5=

[(5+25)+25]:5=

(30+25):5=

55:5=11

b)

80+[26-(81:9+4)]=

80+[26-(9+4)]=

80+(26-13)=

80+13=93

c)

200–[50:5+(76-28)+7]+15=

200-(10+48+7)+15=

200-(58+7)+15=

200-65+15=

135+15=150

d)

793+200:10-[76+(293-209)]=

793+20-(76+84)=

793+20-160=

813-160=653

e)

[(4:4+4):5+9]×222=

[(1+4):5+9]×222=

(5:5+9)×222=

(1+9)×222=

10×22×=2220

f)

[(58×3-74)×100:1000+(111×9+111)]+889=

[(174-74)×100:1000+(999+111)]+889=

(100×100:1000+1110)+889=

(10000:1000+1110)+889=

(10+1110)+889=

1120+889=2009

g)

606+2484:9-[248:4+(2596-2499)-99]-666=

606+276-(62+97-99)-666=

606+276-(159-99)-666=

606+276-60-666=

882-60-666=

822-666=156

h)

(6518-3462-362)-[2694:(1103-1097)]=

(3056-362)-(2694:6)=

2694-449=2245

i)

2976+[(3785-2986)×3]-5188=

2976+(799×3)-5188=

2976+2397-5188=

5373-5188=185

j)

[(2+2+2):2-2×1]×[(3+3+3):3-3×1]+1=

[(4+2):2-2×1]×[(6+3):3-3×1]+1=

(6:2-2×1)×(9:3-3×1)+1=

(3-2)×(3-3)+1=

1×0+1=

0+1=1

k)

(280-78):2×5+[(378+88):2+262]=

202:2×5+(466:2+262)=

101×5+(233+262)=

505+495=1000

l)

2×[12×10:6-(200-20):9+36:18-2]=

2×(120:6-180:9+2-2)=

2×(20-20+2-2)=

2×(0+2-2)=

2×(2-2)=

2×0=0

m)

1500-13×5+[25×(160-30×5)-8-(24+6:6)]=

1500-55+[25×(160-150)-8-(24+1)]=

1500-55+(25×10-8-25)=

1500-55+(250-8-25)=

1500-55+(242-25)=

1500-55+217=

1445+217=1662

n)

5×{32:8+5×[40+8×(200:5-72:2)]}=

5×{4+5×[40+8×(40-36)]}=

5×[4+5×(40+8×4)]=

5×[4+5×(40+32)]=

5×(4+5×72)=

5×(4+360)=

5×360=1800

o)

0+6×{36:9+0×[37+9×(400:5-96:3)]}=

6×{4+0×[37+9×(80-32)]}=

6×[4+0×(37+9×48)]=

6×[4+0×(37+432)]=

6×(4+0×469)=

6×(4+0)=

6×4=24

p)

1500+{250:5+5×[265-(50:25+2)×65]×150}=

1500+{50+5×[265-(2+2)×65]×150}=

1500+[50+5×(265-3×65)×150]=

1500+[50+5×(265-195)×150]=

1500+(50+5×70×150)=

1500+(50+350×150)=

1500+(50+52500)=

1500+52550=54050

q)

1278-2×{316+4×[6+(3+3×3):6]}=

1278-2×{316+4×[6+(3+9):6]}=

1278-2×[316+4×(6+12:6)]=

1278-2×[316+4×(6+2)]=

1278-2×(316+4×8)=

1278-2×(316+32)=

1278-2×348=

1278-696=582

r)

16+(15:3+3):8+[16-(3×20-50)-5+6]+3=

16+(5+3):8+[16-(60-59)-5+6]+3=

16+8:8+(16-10-5+6)+3=

16+1+(6-5+6)+3=

16+1+(1+6)+3=

16+1+7+3=

17+7+3=

24+3=27

sper că te-am ajutat