Question

(√27-2√3+√5)(√125+√3-6√5)

Answer 1

(√27-2√3+√5)(√125+√3-6√5)= (3√3-2√3+√5)(5√5+√3-6√5) = (√3+√5)(√3-√5)= (√3)²- (√5)²
= 3-5= -2. 

Answer 2

(3$\sqrt{3}$-2$\sqrt{3}$+$\sqrt{5}$)(5$\sqrt{5}$+$\sqrt{3}$-6$\sqrt{5}$)=($\sqrt{3}$+$\sqrt{5}$)($\sqrt{3}$-$\sqrt{5}$)=3-5=-2