Question

(√27-√363):√3
(√72-√288):√2
(3√675-2√507):(-√3)​

Answer 1

Răspuns:

$\sqrt{27} = \sqrt{ {3}^{3} }$

$\sqrt{363} = \sqrt{ {11}^{2} \times3 }$

$\frac{( 3\sqrt{3} - 11 \sqrt{3} )}{ \sqrt{3} } = \frac{ \sqrt{3} (3 - 11)}{ \sqrt{3} } = - 8$

$\sqrt{72} = \sqrt{2 \times {6}^{2} }$

$\sqrt{288} = \sqrt{2 \times {12}^{2} }$

$\frac{( \sqrt{72} - \sqrt{288} ) }{ \sqrt{2} } = \frac{6 \sqrt{2} - 12 \sqrt{2} }{ \sqrt{2} } = - 6$

$\sqrt{675} = \sqrt{3 \times 225 } = \sqrt{3 \times {15}^{2} } = 5 \sqrt{3}$

$\sqrt{507} = \sqrt{3 \times 169} = \sqrt{3 \times {13}^{2} } = 13 \sqrt{3}$

$(3 \sqrt{675} - 2 \sqrt{507} ) \div ( - \sqrt{3} ) = 3 \times 5 \sqrt{3} - 2 \times 13 \sqrt{3} ) \div ( - \sqrt{ 3} ) = - 15 + 26 = 11$