Question

2⁷:4³+3⁹•27⁵:3²⁰+(3¹•2⁴-4²):2³=​

Answer 1

Răspuns: $\bf \red{\underline{87}}$

Explicație pas cu pas:

$\bf 2^7:4^3+3^9\cdot27^5:3^{20}+(3^1\cdot2^4-4^2):2^3=$

$\bf 2^7:(2^{2})^3+3^9\cdot(3^{3})^5:3^{20}+[3^1\cdot2^4-(2^{2})^2]:2^3=$

$\bf 2^7:2^{2\cdot 3}+3^9\cdot 3^{3\cdot5}:3^{20}+\big(3\cdot2^4-2^{2\cdot2}\big):2^3=$

$\bf 2^7:2^{6}+3^9\cdot 3^{15}:3^{20}+\big(3\cdot2^4-2^{4}\big):2^3=$

$\bf 2^{7-6}+3^{9+15-20}+2^{4}\cdot\big(3\cdot2^{4-4}-2^{4-4}\big):2^3=$

$\bf 2^{1}+3^{4}+\big[2^{4}\cdot\big(3\cdot2^{0}-2^{0}\big)\big]:2^3=$

$\bf 2+3^{4}+\big[2^{4}\cdot\big(3\cdot1-1\big)\big]:2^3=$

$\bf 2+3^{4}+\big(2^{4}\cdot2\big):2^3=$

$\bf 2+3^{4}+2^{4+1-3}=2+81+2^{2}=$

$\bf 2+81+4 =\red{\underline{87}}$

$==pav38==$    

Answer 2

$\it =2^7:2^6+3^9\cdot3^{15}:3^{20}+(3\cdot16-16):8=2+3^{9+15-20}+32:8=\\ \\ =2+81+4=87$