Question

27. Aflati trei numere consecutive al caror produs este: a) 46 620. b) 110 544. c) 166 320


Urgent va rog!!

Answer 1

a) 46620 = 35·36·37

b) 110544 = 47·48·49

c) 166320 = 54·55·56

a) 46620 b) 110544 c) 166320

a) 46620 = a·(a-1)·(a+1) = (a-1)·a·(a+1)

a ≈ ∛46620 ≈ 35,99 ≈ 36

a = 36 => a-1 = 35 => a +1 = 37

(a-1)·a·(a+1) = 35·36·37 = 46620

b) (b-1)·b·(b+1) = 110544

b ≈ ∛110544 ≈ 47,99 ≈ 48

b = 48 ; b-1 = 47 ; b+1 = 49

(b-1)·b·(b+1) =47·48·49 = 110544

c) (c-1)·c·(c+1) = 166320

c ≈ ∛166320 ≈ 54,99 ≈ 55

c = 55 ; c-1 = 54 ; c+1 = 56

(c-1)·c·(c+1) = 54·55·56 = 166320

COROANA TE ROG!!