Question

(2777+556):1111+[7x(296-170)]:6=
[2093+15236:13-(101-96)]x10+101=
[(276x41-32):52+83]:(1900-1850)=
[(13312:16-132:2)x16:8]+1652=

Answer 1

Răspuns:

Salutare!

(2777+556):1111+[7×(296-170)]:6=

3 333:1 111+(7×126):6=

3+882:6=

3+147=

150

[2 093+15 236:13-(101-96)]×10+101=

(2 093+1 172-5)×10+101=

(3 265-5)×10+101=

3 260×10+101=

32 601+101=

32 701

[(276×41-32):52+83]:(1 900-1 850)=

[(11 316-32):52+83]:50=

(11 284:52+83):50=

(217+83):50=

300:50=

6

[(13 312:16-132:2)×16:8]+1 652=

[(832-66)×16:8]+1 652=

(766×16:8)+1 652=

(12 256:8)+ 1652=

1 532+1 652=

3 184

Baftă!