Question

√28+(1+√ 2)²-√8+(1-√7)²=?

Answer 1

$\sqrt{28} +(1+ \sqrt{2} )^2- \sqrt{8} +(1- \sqrt{7} )^2= \\ =2 \sqrt{7} +1^2+2 \cdot 1 \cdot \sqrt{2} + \sqrt{2} ^2-2 \sqrt{2} +1^2-2 \cdot 1 \cdot \sqrt{7} + \sqrt{7} ^2= \\ =2 \sqrt{7} +1+2 \sqrt{2} +2-2 \sqrt{2} +1-2 \sqrt{7} +7=11$

Answer 2

Ai rezolvarea mai jos.