Question

(28)^2:2^2^4×(3^2-1)-3^0×2^3​

Answer 1

28²:2⁸×(3²-1)-3⁰×2³ =

= 784:2⁸×(3²-1)-3⁰×2³=

784|2

392|2

196|2

98|2

49|7

7|7

1 => 784=2⁴+7²

=(7²+2⁴):2⁸×(3²-1)-3⁰×2³=

=7²:2⁸+2‐⁴×8-2³=

=7²:2⁸+2-⁴×2³-2³=

=7²:2⁸+2-¹-2³=

=2(7²:2⁷-1-4)=

=2(7²:2⁷-5)=

=2(49:128-5)...

Answer 2

Răspuns:

Explicație pas cu pas:

(28)^2:2^2^4×(3^2-1)-3^0×2^3​=2^4·7²:2^8·(9-1)-1·8=7²/4²·8-8=

=7²-8=49-8=41