Question

2800÷100÷7+{(154-23×6)÷8+[100-(132÷4+2)×2]}÷6=
Va rog dau coronita

Answer 1

2800:100:7+{( 154-23*6):8+[100-(132:4+2)*2]}:6=

1) 132:4=33
2)33+2=35
3)35*2=70
4)100-70=30
5)23*6=138
6)154-138=16
7)16:8=2
8)2+30=32
9)2800:100=28
10)28:7=4
11)32:6=5$\frac{1}{3}$
12)$5\frac{1}{3}$ +4=9$\frac{1}{3}$

Answer 2

2800:100:7+{(154-23×6):8+[100-(132:4+2)×2]}:6=28/3

2800:100:7+{(154-138):8+[100-(33+2)×2]}:6=
=2800:100:7+[16:8+(100-35*2)]:6=
=2800:100:7+[16:8+(100-70)]:6=
=2800:100:7+(16:8+30):6=
=2800:100:7+(2+30):6=
=2800:100:7+32:6=
=28:7+32:6=
=4+32:6=   simplificam cu 2 fractia, avem:
=4+16:3=   numitor comun 3
=(3*4)/3+16/3=12/3+16/3=(12+16)/3=28/3
sau poti scrie ca 9intreg 1/3