Question

280g zinc de puritate 82% reactioneaza cu acid clorhidric. Ce masa de clorura de zinc se formeaza si cati moli de hidrogen se degaja.

Ajutorr

Answer 1

puritatea = m pur/m impur*100 -> mpur= 82*280/100=229,6g Zn pur

MZn=65g/mol

MZnCl2=AZn+2ACl=65+2*35,5=136g/mol

n=m/M=229,6/65=3,5323 moli Zn

Zn + 2HCl -> ZnCl2 + H2

65g Zn.....................136g ZnCl2
229,6g Zn...................xg ZnCl2

x=136*229,6/65= Calculeaza !!

1 mol Zn..........................1 mol H2
3,5323 moli Zn.................3,5323 moli H2