Question

(28x5+30):10+729:9-[25x(39-19x2)]=


(57x2:3)+32x50-[39x(4+2):2]+8=


[(248:8-21x1):10]+(500:50+800:20)=


29x3-38+[2000-(17x2+39x1:3)]=


68:2+[564:6+(31x2+15x3-117:3)]=

Vă rog cât de repede se poate...măcar 2 sau 3 exerciții

Answer 1

Răspuns:1) 3х = 28 - х 3х + х = 28 4х = 28 х = 28 : 4 х = 7 ----------------------- 3 * 7 = 28 - 7 21 = 28 - 7 21 = 21 2) 5х + 12 = 8х + 30 5х - 8х = 30 - 12 - 3х = 18 х = 18 : (- 3) х = - 6 ------------------------------------------- 5 * (- 6) + 12 = 8 * (- 6) + 30 - 30 + 12 = - 48 + 30 - 18 = - 18 3) 33 + 8х = - 5х + 72 8х + 5х = 72 - 33 13х = 39 х = 39 : 13 х = 3 ------------------------------------ 33 + 8 * 3 = - 5 * 3 + 72 33 + 24 = - 15 + 72 57 = 57 4) 6х - 19 = - х - 10 6х + х = - 10 + 19 7х = 9 х = 9/7 x = 1 2/7 ---------------------------------- 6 * 1 2/7 - 19 = - 1 2/7 - 10 6 * 9/7 - 19 = - 11 2/7 54/7 - 19 = - 11 2/7 7 5/7 - 19 = - 11 2/7 - 11 2/7 = - 11 2/7 5) 0,7 - 0,2х = 0,3х - 1,8 - 0,2х - 0,3х = - 1,8 - 0,7 - 0,5х = - 2,5 х = - 2,5 : (- 0,5) х = 5 -------------------------------------------- 0,7 - 0,2 * 5 = 0,3 * 5 - 1,8 0,7 - 1 = 1,5 - 1,8 - 0,3 = - 0,3 6) 0,1х + 9 = 0,2х - 4 0,1 х - 0,2х = - 4 - 9 - 0,1х = - 13 х = - 13 : (- 0,1) х = 130 -------------------------------------------------- 0,1 * 130 + 9 = 0,2 * 130 - 4 13 +

9 = 26 - 4 22 = 22

Explicație pas cu pas:cred ca asa

Answer 2

Bună!

. . . . . . . . . . . . . . .

(28·5+30)÷10+729÷9–[25·(39–19·2)]=

(28·5+30)÷10+729÷9–(25·1)=

(28·5+30)÷10+729÷9–25=

170÷10+729÷9–25=

17+729÷9–25=

17+81–25=

98–25=73

. . . . . . . . . . . . . .

(57·2÷3)+32·50–[39·(4+2)÷2]+8=

(57·2÷3)+32·50–(39·6÷2)+8=

(57·2÷3)+32·50–(234÷2)+8=

(57·2÷3)+32·50–117+8=

114÷3+32·50–117+8=

38+32·50–117+8=

38+1600–117+8=

1638–117+8=

1638–125=1513

. . . . . . . . . . . . . .

[(248÷8–21·1)÷10]+(500÷50+800÷20)=

[(31–21·1)÷10]+(500÷50+800÷20)=

[(31–21)÷10]+(500÷50+800÷20)=

(10÷10)+(500÷50+800÷20)=

1+(500÷50+800÷20)=

1+(10+800÷20)=

1+(10+40)=

1+50=51

. . . . . . . . . . . . . .

29·3–38+[2000–(17·2+39·1÷3)]=

29·3–38+[2000–(34+39·1÷3)]=

29·3–38+[2000–(34+39÷3)]=

29·3–38+[2000–(34+13)]=

29·3–38+(2000–47)=

29·3–38+1953=

87–38+1953=

49+1953=2002

. . . . . . . . . . . . . .

68÷2+[564÷6+(31·2+15·3–117÷3)]=

68÷2+[564÷6+(62+15·3–117÷3)]=

68÷2+[564÷6+(62+45–117÷3)]=

68÷2+[564÷6+(62+45–39)]=

68÷2+[564÷6+(107–39)]=

68÷2+(564÷6+68)=

68÷2+(94+68)=

68÷2+162=

34+162=196

. . . . . . . . . . . . . .

Sper că te-am ajutat!

◍Succes♡