Question

29............................​

Answer 1

Rezolvare:
f(x)= 2- 3x

$f(\sqrt{2} -1) = 2 - 3(\sqrt{2} -1) = 2 - 3\sqrt{2} +3=5-3\sqrt{2}$
$f(\sqrt{2}) = 2 - 3\sqrt{2}$

$f(\sqrt{2}-1)$ ?  $f(\sqrt{2})$
$5 - 3\sqrt{2}$ ? $2-3\sqrt{2}$ | + $3\sqrt{2}$

5 > 2 ⇒ $f(\sqrt{2}-1)$ > $f(\sqrt{2})$