Question

2⁹+2¹⁰+2¹¹=n×2⁹ determinati nr. natural n
va rog e urgent. raspuns corect=coroana multumesc​

Answer 1

2^9 + 2^10 + 2^11 = n × 2^9

2^9 × (1 + 2 + 2^2) = n × 2^9

2^9 × 7 = n × 2^9

n = 7

Answer 2

$\it 2^9+2^{10}+2^{11}=n\cdot2^9 \Rightarrow 2^{10}+2^{11}=n\cdot2^9-2^9 \Rightarrow \\ \\ \Rightarrow2^{9}\cdot(2+4)=2^9\cdot(n-1)|_{:2^9}\Rightarrow 6=n-1 \Rightarrow n-1=6 \Rightarrow n=7$