Question

2a-3b supra 3a+2b=2 supra 5,aflati a sup ra b

Answer 1

$\frac{2a-3b}{3a-2b}= \frac{2}{5}$=>2(3a+2b)=5(2a-3b)=>6a+2b-10a+15b=0=>-4a+17b=0=>17b=4a=>$\frac{17}{4}$=$\frac{a}{b}$