Question

2CH4= a + 3H2
a + H2O = [b] = c
CH4 + O2 = d + H2O ($400-600^{0}C$ , oxizi de N2)
d + c = e - H2O = f (crotonizare)

Calculeaza masa de compus f care se obtine din 201,6 L (cn) de metan, considerand reactiile totale

Answer 1

2 CH4 = C2H2 + 3 H2
C2H2 + H2O = [CH2=CH-OH] = CH3-CH=O
CH4 + O2 = CH2O + H2O
CH2O + CH3CHO = CH2-CH2-CH=O - H2O => CH2=CH-CH=O
                                 OH
Daca toate reactiile sunt totale, putem scrie
3*22,4 l CH4.............56 g acroleina
201.6 l CH4....................x
x = 168 g acroleina

Answer 2

2CH4 --> C2H2 + 3H2
C2H2 + H2O ---> CH2=CH(OH) ---> CH3-CH=O
CH4 + O2 ---> CH2O + H2O
CH3-CH=O + CH2O ---> CH3-CH2-CH=O ---H2O--> CH2=CH-CH=O
n=V/Vm=201.6/22.4=9 moli CH4
3 mol CH4....................1mol C3H4O
9 mol..........................x=3 mol
n=m/M==>m=n*M=3*56=168g C3H4O
MC3H4O=58g/mol