Question

2laPutereaX + 2LaPutereaX+2 + 2laPuterea x+3=832

Answer 1

$2^{x} + 2^{x+2} + 2^{x+3} =832$
$2^{x} (1+ 2^{2} + 2^{3} )=832$
[tex] 2^{x} *13=832 [/tex]
$2^{x} =832:13$
$2^{x} =64$
$2^{x}= 2^{6}$
x=6